Jumat, 23 November 2012

Benarkah 1 = 2 ????

Benarkah 1 = 2 ????

BUKTI (1)
3.1 = 1+1+1 (1 sebanyak 3)
Analog
x.x = x+x+x+.....+x (x sebanyak x)
x^2 = x+x+x+.....+x
diferensialkan kedua ruas
d(x^2) = d(x+x+x+.....+x)
Ruas kiri
d(x^2) = 2x
Ruas kanan
d(x+x+x+.....+x) = 1+1+1+.....+1 (1 sebanyak x)
d(x+x+x+.....+x) = 1x
didapat
2x = 1x
2 = 1
1 = 2

BUKTI (2)
definisi dalam bilangan kompleks i :
i = akar(-1)
i^2 = -1

-1/1 = 1/-1
akar(-1/1) = akar(1/-1)
akar(-1) / akar(1) = akar(1) / akar(-1)
i/1 = 1/i
i/2 = 1/(2i)
(i/2) + (3/(2i)) = (1/(2i)) + (3/(2i) )
i ( (i/2) + (3/(2i)) ) = i ( (1/(2i)) + (3/(2i)) )
(-1/2) + (3/2) = (1/2) + (3/2)
2/2 = 4/2
1 = 2

BUKTI (3)
Definisi integral parsial
Int(u dv) = u*v - Int(v du)
Analog
Int(1/x^2 * 2x)dx = 1/x^2 * x^2 - Int(-2/x^3 * x^2)dx
Int(2/x)dx = 1 - Int(-2/x)dx
Int(2/x)dx = 1 + Int(2/x)dx
0 = 1
0+1 = 1+1
1 = 2

@dimana letak kesalahan pembuktian (1), (2) dan (3) di atas? apa alasannya?

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